Suppose there is IP version 6 address 2001:1D11:220A::/48 assigned to an ISP with 16-bit subnet ID. The network administrators can subnet the IP version 6 address just counting /16-bit subnet ID in hexadecimal. This would allow the administrator to create 65,536 /64 subnet. The table below illustrates the subnetting procedure of IPv6 address.
IPv6 Range. |
---|
2001:1D11:220A:0000::/48 |
2001:1D11:220A:0001::/48 |
2001:1D11:220A:0002::/48 |
2001:1D11:220A:0003::/48 |
2001:1D11:220A:0004::/48 |
2001:1D11:220A:0005::/48 |
2001:1D11:220A:0006::/48 |
2001:1D11:220A:0007::/48 |
2001:1D11:220A:0008::/48 |
2001:1D11:220A:0009::/48 |
2001:1D11:220A:000A::/48 |
2001:1D11:220A:000B::/48 |
2001:1D11:220A:000C::/48 |
2001:1D11:220A:000D::/48 |
2001:1D11:220A:000E::/48 |
2001:1D11:220A:000F::/48 |
2001:1D11:220A:0010::/48 |
2001:1D11:220A:0011::/48 |
2001:1D11:220A:0013::/48 |
2001:1D11:220A:0014::/48 |
2001:1D11:220A:0015::/48 |
UPTO |
2001:1D11:220A:FFFF::/48 |
IP address | 2001:1d11:220a::/48 |
type | GLOBAL-UNICAST |
network | 2001:1d11:220a:: |
Prefix length | 48 |
network range | 2001:1d11:220a:0000:0000:0000:0000:0000- 2001:1d11:220a:ffff:ffff:ffff:ffff:ffff |
total IP addresses | 1208925819614629174706176 |
IP address (full) | 2001:1d11:220a:0000:0000:0000:0000:0000 |
integer ID | 42541077709267690993608268614224314368 |
hexadecimal ID | 0x20011d11220a00000000000000000000 |
dotted decimal ID | 32.1.29.17.34.10.0.0.0.0.0.0.0.0.0.0 |
base 85 ID | 9r~el_Jmw%(zRha8Y~WC |
binary ID | 00100000000000010001110100010001… |
ip6.arpa Format | 0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.0.a.0.2.2.1.1.d.1.1.0.0.2.ip6.arpa |
MS ipv6.literal.net | 2001-1d11-220a–.ipv6-literal.net |
now let’s split it into the /64 subnet, If we split it in /64 to a /48 bit we will get 65536 subnets.

and this is how the network will look like as given below .i have fileterd only 32 network but there will be 65536 network.

The hierarchy of subnetting is given below.
